Krylov-Newton algorithm
BifurcationKit
is built upon the newton algorithm for solving (large-dimensional) nonlinear equations
\[F(x)=0\in\mathbb R^n,\quad x\in\mathbb R^n.\]
Writing $J(x)\in\mathcal L(\mathbb R^n)$ the jacobian, the algorithm reads
\[x_{n+1} = x_n - J(x_n)^{-1}F(x_n)\]
with initial guess $x_0$.
The crux of the algorithm is to solve the linear system in $y$:
\[J(x_n)\cdot y = F(x_n).\]
To this end, we never form $J^{-1}$ like with pinv(J)
but solve the linear system directly.
Space of solutions
For the algorithm to be defined, a certain number of operations on x
need to be available. If you pass x::AbstractArray
, you should not have any problem. Otherwise, your x
must comply with the requirements listed in Requested methods for Custom State.
Different Jacobians
There are basically two ways to specify the jacobian:
- Matrix based
- Matrix-free.
In case you pass a matrix (in effect an AbstractMatrix
like a sparse one,...), you can use the default linear solver from LinearAlgebra
termed the backslash operator \
. This is a direct method. This is the case 1 above.
Another possibility is to pass a function J(dx)
and to use iterative linear solvers. In this case, this is termed a Krylov-Newton method. This is the case 2 above. In comparison to the Matrix-based case, there is no restriction to the number of unknowns $n$.
The available linear solvers are explained in the section Linear solvers (LS).
One can find a full description of the Krylov-Newton method in the API.
Simple example
Here is a quick example to show how the basics work. In particular, the problem generates a matrix based jacobian using automatic differentiation.
using BifurcationKit
F(x, p) = x.^3 .- 1
x0 = rand(10)
prob = BifurcationProblem(F, x0, nothing)
sol = newton(prob, NewtonPar(verbose = true))
NonLinearSolution{Vector{Float64}, BifurcationProblem{BifFunction{typeof(Main.F), BifurcationKit.var"#6#21"{typeof(Main.F)}, Nothing, BifurcationKit.var"#4#19"{typeof(Main.F)}, Nothing, BifurcationKit.var"#9#25"{BifurcationKit.var"#d1Fad#23"{typeof(Main.F)}}, BifurcationKit.var"#11#27", BifurcationKit.var"#13#29", BifurcationKit.var"#15#31", Bool, Float64}, Vector{Float64}, Nothing, Setfield.IdentityLens, typeof(BifurcationKit.plotDefault), typeof(BifurcationKit.recordSolDefault)}, Vector{Float64}, Int64}([1.0, 1.0, 1.0, 1.0, 1.0, 1.0, 1.0, 1.0, 1.0, 1.0], ┌─ Bifurcation Problem with uType Vector{Float64}
├─ Inplace: false
├─ Symmetric: false
└─ Parameter: p, [2.174725552362892, 601.8748962378897, 178.02957049874556, 52.45094524597974, 15.256432293420499, 4.263073694761814, 1.0460899556705496, 0.16813682588915324, 0.007937960706706057, 2.082009167780896e-5, 1.444890873614213e-10, 0.0], true, 11, 11)
Example
The (basic) tutorial Temperature model (Simplest example) presents all cases (direct and iterative ones).